Multiples of 3 and 5

Problem 1

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.

#include<iostream>
using namespace std;
int main()
{
    int n = 1000;
    int sum = 0;

    for(int i = 0; i < n; ++i)
        if(i % 3 == 0 || i % 5 == 0)
            sum += i;
    cout<< "Sum below 1000 is:" << sum << endl;
}

板刷PE的开始....