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使用 EntityGraphJpaRepository时报No property 'findOne' found for type

大师的学徒

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2023-05-09

@SpringBootApplication
@EnableJpaRepositories(repositoryFactoryBeanClass = EntityGraphJpaRepositoryFactoryBean.class)
public class AuthApiApplication {

   public static void main(String[] args) {
      SpringApplication.run(AuthApiApplication.class, args);
   }

}

@EnableJpaRepositories(repositoryFactoryBeanClass = EntityGraphJpaRepositoryFactoryBean.class)

这个一定要加

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