Leetcode 7. Reverse Integer (Java)-CFANZ编程社区

Given a signed 32-bit integer x, return x with its digits reversed. If reversing x causes the value to go outside the signed 32-bit integer range [-231, 231 - 1], then return 0.

Assume the environment does not allow you to store 64-bit integers (signed or unsigned).

Example 1:

Input: x = 123
Output: 321

Example 2:

Input: x = -123
Output: -321

Example 3:

Input: x = 120
Output: 21

Constraints:

-231 <= x <= 231 - 1

class Solution {
    public int reverse(int x) {
        int pop=0;
        
        int rev=0;
        
        
        while(x!=0)
        {
            pop=x%10;
            x/=10;
            
            
        
        if(rev>Integer.MAX_VALUE/10||(rev==Integer.MAX_VALUE/10&&pop>7))return 0;
        if(rev<Integer.MIN_VALUE/10||(rev==Integer.MIN_VALUE/10&&pop<-8))return 0;
            rev=rev*10+pop;
        }
        return rev;
    }
}