题目链接:点击打开链接
题目大意:略。
解题思路:略。
AC 代码
SELECT DISTINCT viewer_id id
FROM Views
GROUP BY viewer_id, view_date
HAVING COUNT(DISTINCT article_id) > 1
ORDER BY viewer_id
LeetCode(数据库)- 文章浏览 II
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2022-05-18
题目链接:点击打开链接
题目大意:略。
解题思路:略。
AC 代码
SELECT DISTINCT viewer_id id
FROM Views
GROUP BY viewer_id, view_date
HAVING COUNT(DISTINCT article_id) > 1
ORDER BY viewer_id
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