时间隐写

先用identify分解出时间间隙

转ASCII码

c = 0
a = "779081123687348951031051181019510910195115116481129511610510910133125"
while 1:
    try:
        if int(a[c])>1:
            print(chr(int(a[c:c+2])),end='')
            c+=2
        elif int(a[c])==1:
            print(chr(int(a[c:c+3])),end='')
            c+=3
    except Exception:
        break