题目链接：​​点击打开链接​​

题目大意：略。

解题思路：略。

AC 代码

-- 解决方案(1)
SELECT
    Name
FROM
    Employee AS t1 JOIN
    (SELECT
        ManagerId
    FROM
        Employee
    GROUP BY ManagerId
    HAVING COUNT(ManagerId) >= 5) AS t2
    ON t1.Id = t2.ManagerId
;

-- 解决方案(2)
SELECT e1.Name
FROM Employee e1, Employee e2
WHERE e1.Id = e2.ManagerId
GROUP BY e1.Id
HAVING COUNT(e1.Id) >= 5