题目：原题链接（简单）
标签：字符串
解法 | 时间复杂度 | 空间复杂度 | 执行用时 |
Ans 1 (Python) | O ( N ) | O ( N ) | 40ms (77%) |
Ans 2 (Python) | |||
Ans 3 (Python) |
解法一：
class Solution:
def modifyString(self, s: str) -> str:
s = list(s)
for i in range(len(s)):
if s[i] == "?":
maybe = ["a", "b", "c"]
if i > 0 and s[i - 1] in maybe:
maybe.remove(s[i - 1])
if i < len(s) - 1 and s[i + 1] in maybe:
maybe.remove(s[i + 1])
s[i] = maybe.pop(0)
return "".join(s)
