scala> movies.show(truncate = false)
+-------+---------+-----------------------+
|movieId|movieName|genre                  |
+-------+---------+-----------------------+
|1      |example1 |action|thriller|romance|
|2      |example2 |fantastic|action       |
+-------+---------+-----------------------+

假设有​​DataFrame movies​​​如上所示，要将genre字段按​​|​​切开，并将切开的每个子集保存为一行该如何操作？

scala> movies.withColumn("genre", explode(split($"genre", "[|]"))).show
+-------+---------+---------+
|movieId|movieName|    genre|
+-------+---------+---------+
|      1| example1|   action|
|      1| example1| thriller|
|      1| example1|  romance|
|      2| example2|fantastic|
|      2| example2|   action|
+-------+---------+---------+