5.流程控制:
     1.分支结构:if 
     2.循环:
         for、while
    1.if 
 if_stmt ::=  "if" assignment_expression ":" suite
              ("elif" assignment_expression ":" suite)*
              ["else" ":" suite]
类型转换:
     # 1.类型转换
 n1 = 1
 print(n1)
 # print(n1+"1")
 print(n1,"1")
 print(str(n1) + "1")
 print(int("123") + 20)
if:
 score = float(input("请输入一个数字:"))
 if(score<60):
     print("不及格")
 elif (score<80):
     print("良")
 elif (score <=100):
     print("优秀")
 else:
     print("输入有误")
2.for 
 for_stmt ::=  "for" target_list "in" expression_list ":" suite
               ["else" ":" suite]
java 集合有哪些:
Collection:
     List: 存储元素,有序、可重复
     Set: 存储元素,不可重复、无序
 Map:
     kv:存储一对一对的数据
l1 = [1,2,3,4,"abc","456"]
 for el in l1 :
     print(el)
 else:
     print("xxx")
3.while 
 while_stmt ::=  "while" assignment_expression ":" suite
                 ["else" ":" suite]
flag  = float(input("请输入一个数字:"))
 while(flag == 1):
     score = float(input("请输入一个数字:"))
     if (score < 60):
         print("不及格")
     elif (score < 80):
         print("良")
     elif (score <= 100):
         print("优秀")
     else:
         print("输入有误")
 else:
     print("退出while")
     4.break  continue
     L1= [1,2,3,4,5]
     for el in L1:
         if(el == 3):
             # break
             continue
             print(el)
         else:
             print(el)
6.常见的数据结构
     1.str : 
         1.常用的函数
         2.字符串插值
     2.集合: 
         List :有序的,数据可重复【列表】
         Set :无序的 数据不可重复    【集合】
         tuple:【元组】
         dict: kv 【字典】 =》 kv
1.str
 s1 = "NingShao"
 s2 = "XinWei"
 print(s1)
 print(s2)
 print(s1 + s2)
# 转义
 s3 = "flink\nspark"
 print(s3)
 s4 =r"flink\nspark"
 print(s4)
# 函数
 print(len(s1))
 print(len(s2))
print(s1.upper())
 print(s2.lower())
s5= "abcDDD"
 s5 = s5.replace('D',"d")
 print(s5) #abcddd =>1 2
s6 = "a,a,a,b,b,b"
L2 = s6.split(",")
 print(L2)
# 字符串插值
 name = "ningshao"
 age = 40
 print(name,age)
 print("name is : "+name,"age is : ",age)
 print(f"name is {name} , age is {age}")
 print("name is {0} , age is {1}".format(name, age))
 2.集合: 
     List : 有序的集合,元素可以重复
 list 类型
 L1 = [1,2,3,4,"abc"]
# 1.取值
 print(L1[0])
 print(L1[0:3]) #左闭右开
 print(L1[-1])
# 2.设置值
 L1[0]="ningshao"
 print(L1)
# 3.添加值
 L1.append(1)
 L1.append("xuanxuan")
 L1.append(1)
 print(L1)
# 4.移除值
 L1.pop(0)
 print(L1)
 L1.remove("xuanxuan")
 print(L1)
del L1[0]
 print(L1)
# 5.函数
 print(len(L1))
 print(L1.__len__())
L2 = [1,2,3,4,1,6,5]
 print(L2)
 L2.sort()
 print(L2)
L2.sort(reverse=True)
 print(L2)
l3 = sorted(L2,reverse=False)
 print(l3)
 2.tuple  元组
         元组 使用小括号 ,列表使用 方括号
     注意: 
         元组里面的元素是不能被修改的
     tuple    
     t1 = (1,1,1,12,3,"ns","zhege","xw")
     print(t1)
     print(type(t1))
    # 1.取值
     print(t1[0])
     print(t1[0:3])
# 2.添加值
    t2 = t1.__add__((1,2,3))
     print(t2)
     print(t1 + (1, 2, 3))
    # 2.函数
     print(len(t1))
     n = t1.index("zhege")
     print(n)
     m = t1.count(1)
     print(m)
3.set 
     : 不可重复 无序
 s1 = {1,1,1,2,3,4,5,"abc"}
 print(s1 )
 # 1.添加元素
 s1.add(10)
 s1.add("zs")
 print(s1)
s1.remove(10)
 print(s1)
s1.pop()
 s1.pop()
 print(s1)
 # 交 并
 print(s1 & {2, 3, 4})
 print(s1 | {2, 3, 4})
4.dict 
     kv 
 d = {"name":"yusang","age":21,"city":"鞍山"}
 print(d)
 print(type(d))
# 1.取值
 print(d.get("name"))
 print(d.get("age"))
 print(d.get("city"))
# 2.添加kv
 d["gender"]='男'
 print(d)
d["age"]=18
 print(d)
d.pop("name")
 print(d)
# 函数
 print(d.items())
 print(d.keys())
 print(d.values())
for k,v in d.items():
     print(f"key is {k} , value is {v}")
集合常用函数:
     1.enumerate:返回list 下标+value
 l1 = [1,2,3,4]
 for index,value in enumerate(l1):
     print(index,value)
    2.zip():将多个list 匹配 形成 一个
 l1 = ["name","age","gender"]
 l2 = ["zs",21,"女"]
 print(zip(l1, l2))
 print(list(zip(l1, l2)))
 for k,v in list(zip(l1, l2)):
 print("key is {0}, value is {1}".format(k,v))
    3.reversed()  :对元素进行 降序
 print(range(1, 10))
 # for el in range(1,10,2):
 #     print(el)
 for i in reversed(range(1, 10, 2)):
     print(i)
7.推导式
     1.python 特性 快速构建 集合
         1.list 推导式
         [x for x in iterable]
 l1 = []
 for el in range(5):
     l1.append(el)
 print(l1)
l2 = [el for el in range(5)]
 print(l2)
        2.set 推导式
 s1 = {el for el in range(10) if el > 4}
 print(s1)
         3.字典推导式
 d1 = {key:key*2 for key in range(10) if key < 3}
 print(d1)
  










