python sqlite3简单操作（原创）
import sqlite3
class CsqliteTable:
    def __init__(self):
        pass

    def linkSqlite3(self):
        self.conn = sqlite3.connect('./data/xiaohai.db')
        self.c = self.conn.cursor()
        print("Opened database successfully")

    def insertTable(self,sql):
        self.c.execute(sql)
        self.conn.commit()
        print("insert success")

    def selectValues(self):
        self.conn = sqlite3.connect('./data/xiaohai.db')
        self.c = self.conn.cursor()
        self.cursor = self.c.execute("SELECT id from t_member;")
        list1=[]
        for row in self.cursor:
            list1.append(row[0])
        return list1

    def updateTable(self):
        self.conn = sqlite3.connect('./data/xiaohai.db')
        self.c = self.conn.cursor()
        self.cursor = self.c.execute("UPDATE t_member set name = '墨轩' where ID='1001';")
        self.conn.commit()

    def delValue(self):
        self.conn = sqlite3.connect('test.db')
        self.c = self.conn.cursor()
        self.c.execute("DELETE from t_member where ID=2;")
        self.conn.commit()
    def closeTable(self):
        print("close table")
        self.conn.close()


if __name__=="__main__":
    sqliteTable=CsqliteTable()
    sqliteTable.linkSqlite3()
    # sql="insert into t_member(id,name) values('3166102029','萧海')"
    # sqliteTable.insertTable(sql)
    # list1=sqliteTable.selectValues()
    sqliteTable.updateTable()
    sqliteTable.closeTable()