Weird Clock

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 3214    Accepted Submission(s): 1190

Problem Description

A weird clock marked from 0 to 59 has only a minute hand. It won't move until a special coin is thrown into its box. There are different kinds of coins as your options. However once you make your choice, you cannot use any other kind. There are infinite number of coins of each kind, each marked with a number d ( 1 <= d <= 1000 ), meaning that this coin will make the minute hand move d times clockwise the current time. For example, if the current time is 45, and d = 2. Then the minute hand will move clockwise 90 minutes and will be pointing to 15.

Now you are given the initial time s ( 1 <= s <= 59 ) and the coin's type d. Write a program to find the minimum number of d-coins needed to turn the minute hand back to 0.

Input

There are several tests. Each test occupies a line containing two positive integers s and d.
The input is finished by a line containing 0 0.

Output

For each test print in a single line the minimum number of coins needed. If it is impossible to turn the hand back to 0, output "Impossible".

Sample Input

30 1 0 0

Sample Output

1

Author

DU, Peng

Source

​​ZOJ Monthly, December 2002 ​​

题解：原来是s分钟，然后每次转s*d分钟，如果是0点就输入转的次数....'

AC代码：

#include<iostream>
#include<cstdlib>
#include<cstdio>
#include<cmath>
#include<cstring>
#include<string>
#include<cstdlib>
#include<iomanip>
#include<algorithm>
#include<time.h>
typedef long long LL;
using namespace std;
int main()
{
    int s,d;
    while(cin>>s>>d)
    {
        if(s==0&&d==0)break;
        int i=0;
        while(s%60)
        {
            s+=(d*s)%60;  //去掉%60就会WA 
            i++;
            if(i>10000)
                break;
        }
        if(i<=10000)
            cout<<i<<endl;
        else
            cout<<"Impossible"<<endl;    
    }
    return 0;    
}