392.判断子序列

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2022-11-07


392.判断子序列

392.判断子序列_i++

题解:

双指针遍历

class Solution {
public boolean isSubsequence(String s, String t) {
int n = s.length(), m = t.length();
int i = 0, j = 0;
while(n > i && m > j){
if(s.charAt(i) == t.charAt(j)){
i++;
}
j++;
}
return i == n;
}
}


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