题目：​​原题链接​​（中等）

标签：动态规划、滑动窗口、字符串

解法一：

class Solution:
    def wordBreak(self, s: str, wordDict: List[str]) -> bool:
        if not wordDict:
            return False

        words = set(wordDict)
        max_length = max(len(word) for word in words)

        window = collections.deque([0])
        for i2 in range(1, len(s) + 1):
            if i2 - window[0] > max_length:
                window.popleft()
            if not window:
                return False
            for i1 in window:
                if s[i1:i2] in words:
                    window.append(i2)
                    break

        return window[-1] == len(s)