题目链接:点击打开链接
题目大意:略。
解题思路:略。
AC 代码
SELECT query_name, ROUND(AVG(rating / position), 2) quality, ROUND(COUNT(IF(rating < 3, 1, null)) / COUNT(*) * 100, 2) poor_query_percentage
FROM Queries
GROUP BY query_name
LeetCode(数据库)- 查询结果的质量和占比
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2022-05-18
题目链接:点击打开链接
题目大意:略。
解题思路:略。
AC 代码
SELECT query_name, ROUND(AVG(rating / position), 2) quality, ROUND(COUNT(IF(rating < 3, 1, null)) / COUNT(*) * 100, 2) poor_query_percentage
FROM Queries
GROUP BY query_name
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