1.利用RadASM 写汇编程序

本文介绍利用RedASM写一个messageBox “hello world”.

.386
.model flat, stdcall
option casemap :none

include windows.inc
include kernel32.inc
include masm32.inc
includelib kernel32.lib
includelib masm32.lib

.data
helloWorld db "hello world",0

.code
start:
invoke StdOut, addr helloWorld
invoke ExitProcess,0

end start

2.习题：有1、2、3、4个数字，能组成多少个互不相同且无重复数字的三位数？都是多少？
写成c代码很简单：

void p1_fun()

{

for (int i = 1; i <= 4; ++i){

for (int j = 1; j <= 4; ++j){

for (int k = 1; k <=4; ++k){

if (i !=j && i !=k && j != k){

ostringstream stringStream;

stringStream<<i<<j<<k;

cout<<stringStream.str()<<",";

}

　　用汇编实现如下

Title: Hello world

;Author: sld6666666@gmail.com

;Data: 2012-11-29

;Description: Assemble hello world

.386 ;¸Ã³ÌÐò¶ÔCPUµÄ×îµÍÒªÇóÊÇintel 386

.model flat, stdcall ; Æ½Ì¹ÄÚ´æÄ£ÐÍ£¬ stacll º¯Êýµ÷ÓÃ·½Ê½

.stack 4096 ;Õ»µÄ´óÐ¡Îª4096B

option casemap:none

;include Í·ÎÄ¼þ£¬ Á¬½Ó¿â

include msvcrt.inc

includelib msvcrt.lib

.data ;Êý¾Ý¶Î

index_0 dd dword

index_1 dd dword

index_2 dd dword

szFmt db '%d%d%d', 0

entryFmt db ' ',0

.code

start:

mov index_0, 0

forProcess_0:

cmp index_0, 5

jge rtnProcess

inc index_0

mov index_1, 0

forProcess_1:

cmp index_1, 5

jge forProcess_0

inc index_1

mov index_2, 0

forProcess_2:

cmp index_2, 5

jge forProcess_1

inc index_2

mov eax, index_0

mov ebx, index_1

mov edx, index_2

cmp eax, ebx

je forProcess_2

cmp eax, edx

je forProcess_2

cmp ebx, edx

je forProcess_2

invoke crt_printf, addr szFmt,eax, ebx, edx

invoke crt_printf, addr entryFmt

jmp forProcess_2

rtnProcess:

ret

end start