一、题目要求
二、参考代码
n = eval(input())
s = input().split()
count = 0
for i in range(n):
for j in range(i+1,n):
if (eval(s[i]) == -eval(s[j])):
count += 1
break
print(count)
CCF201403-1:相反数(python)
阅读 49
2022-01-31
n = eval(input())
s = input().split()
count = 0
for i in range(n):
for j in range(i+1,n):
if (eval(s[i]) == -eval(s[j])):
count += 1
break
print(count)
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