(数据结构复习day4)
#include <iostream>
using namespace std;
typedef int ElemType;
typedef struct StackNode {
ElemType data;
struct StackNode* next;
}StackNode, * LinkStack;
bool InitStack(LinkStack//初始化链栈
bool Push(LinkStack& S, ElemType e);//将元素e压入栈中
bool Pop(LinkStack& S, ElemType//将首元素出栈,用元素e返回
bool StackEmpty(LinkStack S);//判断链栈是否为空
bool GetTop(LinkStack S, ElemType//取链栈栈顶元素,用元素e返回
void TraverseStack(LinkStack S);//自顶向下遍历栈
bool DestroyStack(LinkStack//销毁链栈
int StackLength(LinkStack S);//返回链栈长度
void conversion(int n, int r);//栈的应用,进制转换
bool InitStack(LinkStack& S) {
S = NULL;
return 1;
}
bool Push(LinkStack& S, ElemType e) {
StackNode* temp = new StackNode;
if (!temp)return 0;
temp->data = e;
temp->next = S;
S = temp;
return 1;
}
bool Pop(LinkStack& S, ElemType& e) {
if (S == NULL)return 0;
StackNode* temp = S;
e = S->data;
S = S->next;
delete temp;
return 1;
}
bool StackEmpty(LinkStack S) {
if (S == NULL)
return 1;
return 0;
}
bool GetTop(LinkStack S,ElemType& e){
if (S == NULL)return 0;
e = S->data;
return 1;
}
void TraverseStack(LinkStack S) {
if (!StackEmpty(S)) {
while (S) {
cout << S->data << " ";
S = S->next;
}
}
cout << endl;
}
bool DestroyStack(LinkStack& S) {
StackNode* temp = S;
if (!StackEmpty(S)) {
while (S) {
S = S->next;
delete temp; temp = S;
}
}
return 1;
}
int StackLength(LinkStack S) {
int n = 0;
while (S) {
n++;
S = S->next;
}
return n;
}
void conversion(int n, int r) {
int e = 0; int m = n;
LinkStack S; InitStack(S);
while (n) {
Push(S, n % r);
n = n / r;
}
cout << m << "转化为" << r << "进制数为:";
while (S != NULL) {
Pop(S, e);
cout << e;
}
}
int main()
{
LinkStack S;
int n, i;
ElemType e;
if (InitStack(S))
cout << "初始化链栈成功" << endl;
else {
cout << "初始化链栈失败" << endl;
return 1;
}
cout << "请输入链栈元素个数:" << endl;
cin >> n;
cout << "请输入链栈元素:" << endl;
for (i = 0; i < n; i++) {
cin >> e;
Push(S, e);
}
cout << "栈中元素为";
if (StackEmpty(S))//检验链栈是否为空
cout << "线性表为空" << endl;
else {
if (GetTop(S, e))
cout << "栈顶元素为" << e << endl;
cout << "自顶向下遍历:\n";
TraverseStack(S);
DestroyStack(S);
}
int r;
cout << "将十进制数转化为r(1<r<10)进制数,输入r: " << endl;
cin >> r;
cout << "输入要转化的数: " << endl;
cin >> n;
conversion(n, r);
return 0;
}
实验样例