求5！
# include <studio.h>
int main(){
int i,t;
t=1;
i=2;
while (i<=5){
t=t*i
i=i+1
}
printf("%d\n",t);
return 0;
}
求1-1/2+1/3-1/4+........+1/99-1/100的值
#include <studio.h>
int main(){
int sign=1;
double deno=2.0,sum=1.0,term;
while(deno<=100){
sign=-sign;
term=sign/deno;
sum=sum+term;
deno=deno+1;
}
printf("%f\n",sum);
return 0;
}
枚举类型：enum
空类型：void
心有猛虎,细嗅蔷薇
