题目链接:点击打开链接
题目大意:略。
解题思路:略。
AC 代码
-- 解决方案(1)
with t as (
select employee_id from Employees
union all
select employee_id from Salaries)
select employee_id from t
group by employee_id
having count(employee_id)=1
order by employee_id
-- 解决方案(2)
WITH t AS (SELECT employee_id FROM Employees
UNION
SELECT employee_id FROM Salaries)
SELECT *
FROM t
WHERE employee_id NOT IN (SELECT e.employee_id FROM Employees e JOIN Salaries s USING(employee_id))
ORDER BY employee_id