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[leetcode] 1446. Consecutive Characters

苦茶如歌 2022-08-11 阅读 21


Description

Given a string s, the power of the string is the maximum length of a non-empty substring that contains only one unique character.

Return the power of the string.

Example 1:

Input: s = "leetcode"
Output: 2
Explanation: The substring "ee" is of length 2 with the character 'e' only.

Example 2:

Input: s = "abbcccddddeeeeedcba"
Output: 5
Explanation: The substring "eeeee" is of length 5 with the character 'e' only.

Example 3:

Input: s = "triplepillooooow"
Output: 5

Example 4:

Input: s = "hooraaaaaaaaaaay"
Output: 11

Example 5:

Input: s = "tourist"
Output: 1

Constraints:

  • 1 <= s.length <= 500
  • s contains only lowercase English letters.

分析

题目的意思是:找出字符串中字符连续出现的最大频率,思路也是很直接,从左到右遍历进行统计字符就行了,当碰到跟前面字符不相等时,则需要置1,重新计数就行了,遍历过程中维护最大频率值res。

代码

class Solution:
def maxPower(self, s: str) -> int:
prev=''
cnt=0
res=1
for ch in s:
if(prev==ch):
cnt+=1
else:
cnt=1
prev=ch
res=max(res,cnt)
return res

参考文献

​​[LeetCode] solution​​


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