开发中经常遇到Xml和Json格式的数据需要进行相关的业务处理,虽然可以直接操作Xml或Json,但是转换成对象操作可以更方便的在系统中传递和操作。尤其是系统间使用报文形式通信时,需要对象和Xml或Json互相转换。
操作Json这里使用Json.Net,需要通过Nuget安装 “ Newtonsoft.Json”;
安装命令:Install-Package Newtonsoft.Json -Version 13.0.1
参考代码:
public class SerializtionDemo
{
public static void DemoMain()
{
Root root = XmlDeserialize<Root>(GetXmlStr());
string Xml = XmlSerialize(root);
Console.WriteLine($"Xml:{Xml}");
string Json = JsonSerialize(root);
Root root2 = JsonDeserialize<Root>(Json);
Console.WriteLine($"Json:{Json}");
Console.Read();
}
/// <summary>
/// 提供初始Xml字符串
/// </summary>
/// <returns></returns>
private static string GetXmlStr()
{
StringBuilder sb = new StringBuilder();
sb.Append("<?xml version=\"1.0\" encoding=\"utf-8\"?>");
sb.Append("<root>");
sb.Append("<data>");
sb.Append("<d1>1</d1>");
sb.Append("<d1>2</d1>");
sb.Append("<d1>3</d1>");
sb.Append("</data>");
sb.Append("</root>");
return sb.ToString();
}
/// <summary>
/// Xml转对象
/// </summary>
/// <typeparam name="T"></typeparam>
/// <param name="xml"></param>
/// <returns></returns>
private static T XmlDeserialize<T>(string xml) where T : class
{
using MemoryStream stream = new MemoryStream(Encoding.UTF8.GetBytes(xml));
using XmlReader reader = XmlReader.Create(stream);
T result = (T)new XmlSerializer(typeof(T)).Deserialize(reader);
return result;
}
/// <summary>
/// 对象转Xml
/// </summary>
/// <typeparam name="T"></typeparam>
/// <param name="Obj"></param>
/// <returns></returns>
private static string XmlSerialize<T>(T Obj) where T : class
{
XmlDocument xmlDocument = new XmlDocument();
using MemoryStream stream = new MemoryStream();
XmlSerializer serializer = new XmlSerializer(typeof(T));
serializer.Serialize(stream, Obj);
stream.Position = 0;
xmlDocument.Load(stream);
return xmlDocument.InnerXml;
}
/// <summary>
/// Json字符串转对象
/// </summary>
/// <typeparam name="T"></typeparam>
/// <param name="json"></param>
/// <returns></returns>
private static T JsonDeserialize<T>(string json)
{
return JsonConvert.DeserializeObject<T>(json);
}
private static string JsonSerialize<T>(T Obj)
{
return JsonConvert.SerializeObject(Obj);
}
[XmlRoot("root")]
public class Root
{
[XmlElement("data")]
public Data data;
}
public class Data
{
[XmlElement("d1")]
public List<int> d1s;
}
}
输出结果: