- 循环list中的所有元素然后删除重复
1. public static List removeDuplicate(List list) {
2. for ( int i = 0 ; i < list.size() - 1 ; i ++ ) {
3. for ( int j = list.size() - 1 ; j > i; j -- ) {
4. if (list.get(j).equals(list.get(i))) {
5. list.remove(j);
6. }
7. }
8. }
9. return list;
10. }
2. 通过HashSet踢除重复元素
1. public static List removeDuplicate(List list) {
2. HashSet h = new HashSet(list);
3. list.clear();
4. list.addAll(h);
5. return list;
6. }
3. 删除ArrayList中重复元素,保持顺序
1. // 删除ArrayList中重复元素,保持顺序
2. public static void removeDuplicateWithOrder(List list) {
3. new HashSet();
4. new ArrayList();
5. for (Iterator iter = list.iterator(); iter.hasNext();) {
6. Object element = iter.next();
7. if (set.add(element))
8. newList.add(element);
9. }
10. list.clear();
11. list.addAll(newList);
12. " remove duplicate " + list);
13. }
4.把list里的对象遍历一遍,用list.contain(),如果不存在就放入到另外一个list集合中
1. public static List removeDuplicate(List list){
2. new ArrayList();
3. for(int i=0;i<list.size();i++){
4. if(!listTemp.contains(list.get(i))){
5. listTemp.add(list.get(i));
6. }
7. }
8. return listTemp;
9. }