import java.util.Scanner;
//题目:输入一个整数n,求从1到n这n个整数的十进制表示中1出现的次数。
//例如输入12,从1到12这些整数中包含1 的数字有1,10,11和12,1一共出现了5次。
public class CiShu {
 public static void main(String args[]) {
  Scanner cin = new Scanner(System.in);
   int a = cin.nextInt();  int result = 0;
   for (int i = 1; i <= a; i++) {
    result = result + contains1num(i);  }
   System.out.print(result);
  } private static int contains1num(int num) {
   int count = 0;  for (int i = 0; i < 6; i++)// 统计的位数
   {
    if (num % Math.pow(10, i + 1) == Math.pow(10, i))
     count++;
    num = (int) (num - num % Math.pow(10, i + 1));  }
  return count;
 }
}