python批量启动多线程

还未了解多线程的请查看博文 ​​python3多线程趣味详解​​

​​python3多线程趣味详解​​​ 只是介绍了 ​​python​​ 多线程的使用，对于批量启动线程来说有些不适用，于是出现如下方法：

建立一个线程池，并将某个线程放入进去

threadpool = []
th = threading.Thread(target=func_name, args=func_args)
threadpool.append(th)

批量加入线程

for i in range(10):
    th = threading.Thread(target=func_name, args=func_args)
    threadpool.append(th)

批量开始线程

for th in threadpool:
        th.start()
for th in threadpool:
    threading.Thread.join(th)

实例如下：

#!/usr/bin/python3.4
# -*- coding: utf-8 -*-

import time
import threading


def matter1(music, test):
    print test, music
    # 假设每一首歌曲的时间是2秒
    time.sleep(2)


if __name__ == '__main__':
    # 设定我要听的歌为
    musics = ["music1", "music2", "music3"]
    test = "122678"
    # 开始时间
    start = time.time()

    threadpool = []

    for music in musics:
        th = threading.Thread(target=matter1, args=(music, test))
        threadpool.append(th)
    for th in threadpool:
        th.start()
    for th in threadpool:
        threading.Thread.join(th)

    # 结束时间
    end = time.time()
    print("完成的时间为：" + str(end - start))

完成同时听三首歌线程，花费时间 ​​2s​​:

限制线程数量可以使用Semaphore，实例如下：

#!/usr/bin/python3.4
# -*- coding: utf-8 -*-

import time
import threading


#添加一个计数器
s1=threading.Semaphore(2)

def matter1(music, test):
    # 计数器获得锁
    s1.acquire()
    print(test, music)
    # 假设每一首歌曲的时间是2秒
    time.sleep(2)
    # 计数器释放锁
    s1.release()


if __name__ == '__main__':
    # 设定我要听的歌为
    musics = ["music1", "music2", "music3"]
    test = "122678"
    # 开始时间
    start = time.time()

    threadpool = []

    for music in musics:
        th = threading.Thread(target=matter1, args=(music, test))
        threadpool.append(th)
    for th in threadpool:
        th.start()
    for th in threadpool:
        threading.Thread.join(th)

    # 结束时间
    end = time.time()
    print("完成的时间为：" + str(end - start))

完成听前2首歌线程，花费时间 ​​2s​​:

听第3首歌花费 ​​2s​​​，最后一共花费 ​​4s​​：