redis为什么快

这是一道典型的贪心算法问题，首先遍历找到一个高度大于0的楼房，然后以此为基准，划分一个区间，找到楼房内高度最小的楼房，每次都减去这个高度最小的值。

后续重复一样，再找减去后楼房高度的最小值，每次减去这个值，直到所有楼房为0.

代码如下：

// 盖楼房
import java.util.Scanner;

public class Solution22 {

    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);

        System.out.print("Enter the number of buildings (n): ");
        int n = scanner.nextInt();

        int[] heights = new int[n];
        System.out.println("Enter the heights of the buildings:");
        for (int i = 0; i < n; i++) {
            heights[i] = scanner.nextInt();
        }

        int operations = minimizeOperations(heights);
        System.out.println("Minimum operations needed: " + operations);
    }

    public static int minimizeOperations(int[] heights) {
        int operations = 0;
        int n = heights.length;

        while (true) {
            int start = -1;
            for (int i = 0; i < n; i++) {
                if (heights[i] > 0) {
                    start = i;
                    break;
                }
            }

            if (start == -1) {
                break; // All buildings are zero height
            }

            int minHeight = heights[start];
            int end = start;
            for (int i = start; i < n && heights[i] > 0; i++) {
                minHeight = Math.min(minHeight, heights[i]);
                end = i;
            }

            for (int i = start; i <= end; i++) {
                heights[i] -= minHeight;
            }

            operations++;
            System.out.println("Operation " + operations + ": Reduce buildings from " + start + " to " + end + " by " + minHeight);
        }

        return operations;
    }
}