0
点赞
收藏
分享

微信扫一扫

java中使用configuration(使用apache的配置文件)

1、pom.xml
[codesyntax lang="xml"]

<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>

<groupId>com.test.pro</groupId>
<artifactId>maven</artifactId>
<version>0.0.1-SNAPSHOT</version>
<packaging>jar</packaging>

<name>maven</name>
<url>http://maven.apache.org</url>

<properties>
<project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
</properties>

<dependencies>
<dependency>
<groupId>junit</groupId>
<artifactId>junit</artifactId>
<version>3.8.1</version>
<scope>test</scope>
</dependency>
<dependency>
<groupId>commons-configuration</groupId>
<artifactId>commons-configuration</artifactId>
<version>1.9</version>
</dependency>
<!-- commons-configuration 自动加载的是2.1的版本,编译时会报错,所以再加上这个 -->
<dependency>
<groupId>commons-lang</groupId>
<artifactId>commons-lang</artifactId>
<version>2.6</version>
</dependency>
</dependencies>

</project>

[/codesyntax]

java文件
[codesyntax lang="java"]

package com.test.pro.maven;

import org.apache.commons.configuration.ConfigurationException;
import org.apache.commons.configuration.PropertiesConfiguration;

public class main {

/**
* @param args
* @throws ConfigurationException
*/
public static void main(String[] args) throws ConfigurationException {
PropertiesConfiguration config = new PropertiesConfiguration("f:\\test.properties");
String userName = config.getString("name");
System.out.println(userName);
}

}

[/codesyntax]

3、配置文件(在F盘下,名称为test.properties)
#test•
name=jianghuiwen

4、输出截图
​​​​

举报

相关推荐

0 条评论