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蓝桥杯练习系统答案-报时助手-Python

大师的学徒 2022-03-11 阅读 57
python算法

3、报时助手

问题描述
  给定当前的时间,请用英文的读法将它读出来。
  时间用时h和分m表示,在英文的读法中,读一个时间的方法是:
  如果m为0,则将时读出来,然后加上“o’clock”,如3:00读作“three o’clock”。
  如果m不为0,则将时读出来,然后将分读出来,如5:30读作“five thirty”。
  时和分的读法使用的是英文数字的读法,其中0~20读作:
  0:zero, 1: one, 2:two, 3:three, 4:four, 5:five, 6:six, 7:seven, 8:eight, 9:nine, 10:ten, 11:eleven, 12:twelve, 13:thirteen, 14:fourteen, 15:fifteen, 16:sixteen, 17:seventeen, 18:eighteen, 19:nineteen, 20:twenty。
  30读作thirty,40读作forty,50读作fifty。
  对于大于20小于60的数字,首先读整十的数,然后再加上个位数。如31首先读30再加1的读法,读作“thirty one”。
  按上面的规则21:54读作“twenty one fifty four”,9:07读作“nine seven”,0:15读作“zero fifteen”。
输入格式
  输入包含两个非负整数h和m,表示时间的时和分。非零的数字前没有前导0。h小于24,m小于60。
输出格式
  输出时间时刻的英文。
样例输入
0 15
样例输出
zero fifteen

暴力解决

##报时助手

def dan(h):##
    x='none'
    if h == 0:
        x = 'zero'
    elif h == 1:
        x = 'one'
    elif h == 2:
        x = 'two'
    elif h == 3:
        x = 'three'
    elif h == 4:
        x = 'four'
    elif h == 5:
        x = 'five'
    elif h == 6:
        x = 'six'
    elif h == 7:
        x = 'seven'
    elif h == 8:
        x = 'eight'
    elif h == 9:
        x = 'nine'
    elif h == 10:
        x = 'ten'
    elif h == 11:
        x = 'eleven'
    elif h == 12:
        x = 'twelve'
    elif h == 13:
        x = 'thirteen'
    elif h == 14:
        x = 'fourteen'
    elif h == 15:
        x = 'fifteen'
    elif h == 16:
        x = 'sixteen'
    elif h == 17:
        x = 'seventeen'
    elif h == 18:
        x = 'eighteen'
    elif h == 19:
        x = 'nineteen'
    elif h == 20:
        x = 'twenty'
    elif h==30:
        x='thirty'
    elif h==40:
        x='forty'
    elif h==50:
        x='fifty'
    return x
def shi(a):
    x='none'
    if a==2:
        x='twenty'
    elif a==3:
        x='thirty'
    elif a==4:
        x='forty'
    elif a==5:
        x='fifty'
    return x
def shuang(h):
    x='none'
    a=h//10
    x=shi(a)
    b=h%10
    y=dan(b)
    x=x+' '+y
    return x

if __name__=='__main__':
    h,m=map(int,input().split())
    x = dan(h)  # 1-20
    if x == 'none':
        x = shuang(h)  # 21-24
    if m==0:#整点
        print(x+" o'clock")
    else:#非整点
        y=dan(m)
        if y=='none':
            y=shuang(m)
        print(x+' '+y)
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